Regex: pull out the numbers

A regular expression describes a text pattern. The re module finds and transforms text that matches it:

import re

re.findall(r"\d+", "a12b3")   # ['12', '3']  — every run of digits
re.sub(r"\s+", "-", "a  b c") # 'a-b-c'       — collapse whitespace

Key pieces: \d matches a digit, + means "one or more", and findall returns every non-overlapping match as a list of strings.

Your task

Write extract_numbers(text) that finds every whole number in text and returns them as a list of ints, in the order they appear.

extract_numbers("order 12 apples and 3 pears")   # [12, 3]
extract_numbers("room 404: not found")           # [404]
extract_numbers("no digits here")                # []

Hint: a findall with a one-or-more-digits pattern (you saw it above) hands you the numbers as strings — then convert each match to an int.